Asked by al sah him
using differential determine the appropriate increase in the surface area of a sphere if the radius increases from 4 cm to 4.05 cm.
Answers
Answered by
Steve
a = 4 pi r^2
da = 8 pi r dr
You have dr = 0.05 and r=4, so
da = 8 pi * 2 * 0.05 = 0.8 pi cm^2
da = 8 pi r dr
You have dr = 0.05 and r=4, so
da = 8 pi * 2 * 0.05 = 0.8 pi cm^2
Answer
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