Asked by chev
What is the maximum value of y if y = x^4 - 8x?
Answers
Answered by
Reiny
Poorly worded question, since there is no maximum value of y = x^4 - 8x
http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E4+-+8x
suppose we blindly proceed as usual ...
dy/dx = 4x^3 - 8
= 0 for a max/min
4x^3 = 8
x^3 = 2
x = 2^(1/3) = appr 1.2599
subbing that in gives us y = appr -7.56 as seen on the graph
using the 2nd derivative test:
y '' = 12x^2 - 8
subbing in x = 2^(1/3) gives a positive, so we are dealing with a minimum, not a maximum
http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E4+-+8x
suppose we blindly proceed as usual ...
dy/dx = 4x^3 - 8
= 0 for a max/min
4x^3 = 8
x^3 = 2
x = 2^(1/3) = appr 1.2599
subbing that in gives us y = appr -7.56 as seen on the graph
using the 2nd derivative test:
y '' = 12x^2 - 8
subbing in x = 2^(1/3) gives a positive, so we are dealing with a minimum, not a maximum
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