Question

Copy of Vector A has a magnitude of 9 and is at an angle of 30.4 degrees measured counter-clockwise from the x axis. Vector B has a magnitude of 12 and is at an angle of 102.3 degrees measured counter-clockwise from the x axis. Vector C has a magnitude of 18 and is at an angle of 180 degrees measured counter-clockwise from the x axis. Lastly, Vector D has a magnitude of 16 and is at an angle of 293.8 degrees measured counter-clockwise from the x axis. If R = A + B + C - D, find the magnitude of R.

Answer 1

R = 9[30.4o] + 12[102.3o] + 18[180o] +
16[293.8o].

X = 9*Cos30.4+12*Cos102.3+18*Cos180+
16*Cos293.8 =

Y = 9*sin30.4+12*sin102.3+18*sin180+
16*sin293.8 =

R = sqrt(X^2 + Y^2).