Asked by Anonymous
a swimmer able to move at 4 mph in still water in order to swim straight across a river from east to west with a southward current of 2 mph which direction should she swim?
Answers
Answered by
Reiny
my diagram consists of a right-angled triangle with a hypotenuse of 4, a height of 2 and a horizontal of x
by Pythagoras,
x^2 + 2^2 = 4^2
x = 2√3 , his actual swimming speed
direction:
sinØ = 2/4
Ø = 30°
by Pythagoras,
x^2 + 2^2 = 4^2
x = 2√3 , his actual swimming speed
direction:
sinØ = 2/4
Ø = 30°
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