from the 2nd equation, 3x = 5y-7
so the 1st equation becomes
2(5y-7)-2y+1 = 0
Now solve that for y, then figure x.
6x-2y+1=0 and 3x-5y+7=0
How do I substitute this?
4 answers
thank you
shouldn't the 2 in 2(5y... be a 6?
no, 3x = 5y-7
So, 6x = 2(5y-7)
So, 6x = 2(5y-7)
2 answers