Asked by tina

6x-2y+1=0 and 3x-5y+7=0

How do I substitute this?
Answered by Steve
from the 2nd equation, 3x = 5y-7
so the 1st equation becomes

2(5y-7)-2y+1 = 0

Now solve that for y, then figure x.
Answered by tina
thank you
Answered by tina
shouldn't the 2 in 2(5y... be a 6?
Answered by Steve
no, 3x = 5y-7
So, 6x = 2(5y-7)
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