Asked by Lisa
If you throw a ball straight up at 10 m/s and release it 2m above the ground:
a) What height will the ball reach
V^2=u^2+2as
0=100+19.6s
s=5.1+2
s=7.1m
b)How long after you release the ball will it hit the ground?
(Answer should be 2.22s but need help getting there)
a) What height will the ball reach
V^2=u^2+2as
0=100+19.6s
s=5.1+2
s=7.1m
b)How long after you release the ball will it hit the ground?
(Answer should be 2.22s but need help getting there)
Answers
Answered by
MathMate
a) correct.
b) use t=sqrt(2h/g)
Time to go up: h=5.1m
Time fall back to the ground: h=7.1m
Add the two times to get your answer.
b) use t=sqrt(2h/g)
Time to go up: h=5.1m
Time fall back to the ground: h=7.1m
Add the two times to get your answer.
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