Question
Given the following information at 25C, calculate G at 25 degrees Celsius
2A(g) B(g) ±£ 3C(g)
Substance Hf (kJ/mol) S(J/molK)
A(g) 191 244
B(g) 70.8 300
C(g) -197 164
a. -956 kJ b. 956 kJ c. 346 kJ
d. 346 kJ e. -1.03 * 10^3 kJ
2A(g) B(g) ±£ 3C(g)
Substance Hf (kJ/mol) S(J/molK)
A(g) 191 244
B(g) 70.8 300
C(g) -197 164
a. -956 kJ b. 956 kJ c. 346 kJ
d. 346 kJ e. -1.03 * 10^3 kJ
Answers
DrBob222
Using dH and dS calculate dGf for A, B, C, then
dGrxn = (n*dGf products) - (n(dGf reactants)
dGrxn = (n*dGf products) - (n(dGf reactants)
nikk
thank you
DrBob222
<b> See the ( and I meant *.</b>
Using dH and dS calculate dGf for A, B, C, then
dGrxn = (n*dGf products) - (n*dGf reactants)
Using dH and dS calculate dGf for A, B, C, then
dGrxn = (n*dGf products) - (n*dGf reactants)