Asked by Merriam
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A train flies 2000km at a bearing of 145° and again 500km at bearing of 270°. Calculate displacement
A train flies 2000km at a bearing of 145° and again 500km at bearing of 270°. Calculate displacement
Answers
Answered by
Henry
D = 2000[145o] + 500[270o].
X = 2000*Cos145 + 500*Cos270 = -1638+0 =
-1638 km.
Y = 2000*sin145 + 500*sin270 = 1147-500 = 647 km.
Q2.
Tan A = Y/X = 647/-1638 = -0.39499.
A = -21.6o N. of W. = 158.4o CCW. =
Direction.
D = X/Cos A = -1638/Cos158.4 = 1762 km.
X = 2000*Cos145 + 500*Cos270 = -1638+0 =
-1638 km.
Y = 2000*sin145 + 500*sin270 = 1147-500 = 647 km.
Q2.
Tan A = Y/X = 647/-1638 = -0.39499.
A = -21.6o N. of W. = 158.4o CCW. =
Direction.
D = X/Cos A = -1638/Cos158.4 = 1762 km.
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