Asked by MiMi
Three hundred people apply for three jobs. 80 of the applicants are women If three persons are selected at random, what is the probability that one is a woman? (Round the answer to six decimal places.)(d) If three persons are selected at random, what is the probability that none is a woman? (Round the answer to six decimal places.)
Answers
Answered by
Reiny
prob(woman) = 80/300 = 2/75
prob(not woman) = 73/75
prob(1 women of 3)
= C(3,1) (2/75)(73/75)^2
= appr .075790
prob(no woman) = (73/75)^3 = .922114
prob(not woman) = 73/75
prob(1 women of 3)
= C(3,1) (2/75)(73/75)^2
= appr .075790
prob(no woman) = (73/75)^3 = .922114
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