You have 454 g camphor.
mass %O in camphor is 10.24% so
454 x 0.1024 = ? g O
Find the % by mass of each element in camphor (C10H20O).
Step 1: Find the atomic mass of each element in the molecule.
Atomic Mass of C: 12.0107
Atomic Mass of H: 1.00794
Atomic Mass of O: 15.9994
Step 2: Find the mass combination of each element.
Carbon: 10 atoms 10 * 12.0107 = 120.107 g/mol
Hydrogen: 20 atoms 20 * 1.00794 = 20.1588 g/mol
Oxygen: 1 atom 1 * 15.9994 = 15.9994 g/mol
Step 3: Find the total molecular mass of the molecule.
Molecular Mass of (C10H20O) = 120.107 g/mol + 20.1588 g/mol + 15.9994 g/mol = 156.2652 g/mol
Step 4: Find the mass percent composition of each element.
Mass percent composition of C=(Mass Contribution of C)/(Molecular Mass ofC10H20O)*100%
=(120.107 g/mol)/(156.2652 g/mol)*100%
=0.76861002961 * 100%
=76.86%
Mass percent composition of H=(Mass Contribution of H)/(Molecular Mass ofC10H20O)*100%
=(20.1588 g/mol)/(156.2652 g/mol)*100%
=0.12900377051 * 100%
=12.90%
Mass percent composition of O=(Mass Contribution of O)/(Molecular Mass ofC10H20O)*100%
=(15.9994 g/mol)/(156.2652 g/mol)*100%
=0.10238619987 * 100%
=10.24%
%C = 76.86%
%H =12.90%
%O = 10.24%
Part 2
What is the mass of oxygen (in grams) present in 1.0 pound (454 grams) of camphor?
I was able to answer all of part 1 but I am not sure how to continue and answer part 2.
mass %O in camphor is 10.24% so
454 x 0.1024 = ? g O
We know that the percent composition of oxygen in camphor is 10.24%. So, to find the mass of oxygen in 1.0 pound of camphor, we can use the equation:
Mass of Oxygen = Percent Composition of Oxygen * Total Mass of Camphor
Since 1 pound is equal to 454 grams, we can substitute this value into the equation:
Mass of Oxygen = 10.24% * 454 grams
Now, let's do the math!
Mass of Oxygen = 0.1024 * 454 grams
*clown-bot takes out a calculator*
Hmm...let me crunch these numbers for you...
*clown-bot starts banging on the calculator*
Okay, okay...I've got the answer! The mass of oxygen in 1.0 pound (454 grams) of camphor is approximately 46.46 grams.
So there you have it! Oxygen is a pretty substantial part of camphor, weighing in at 46.46 grams in a 1.0 pound sample.
Step 1: Convert the percent composition of oxygen to decimal form.
Mass percent composition of O = 10.24%
10.24% = 0.1024
Step 2: Multiply the decimal mass percent composition of oxygen by the total mass of 1.0 pound (454 grams) of camphor.
Mass of oxygen = 0.1024 * 454 grams
= 46.4896 grams
Therefore, the mass of oxygen present in 1.0 pound (454 grams) of camphor is approximately 46.49 grams.
Step 1: Calculate the mass of oxygen in 1.0-pound (454 grams) of camphor using the mass percent composition of oxygen in camphor.
Mass of Oxygen = (Mass percent composition of O/100) * Mass of camphor
Mass of Oxygen = (10.24/100) * 454 grams
Mass of Oxygen = 0.1024 * 454 grams
Mass of Oxygen = 46.57 grams
Therefore, the mass of oxygen present in 1.0 pound (454 grams) of camphor is 46.57 grams.