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Reaction Rate = -(1/2) [d(H2O2)/dt] = [d(O2)/ dt]

Using 25 mL of a 0.2 M hydrogen peroxide solution, the following results are obtained from the equation above: 8.62 mL of gas is collected in 120 seconds. (Assume 760 Torr = 1 atm) Room temperature is 25 degrees C and the vapor pressure of water is 24 Torr.

a) How many moles of oxygen are produced per second?

b) What is the rate of the reaction [d(O2)/dt]?

c) What is the change in the concentration of H2O2 per second?
10 years ago

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