A worker is exposed to 98 dB for five hours and 82 dB for a three hours, giving an eight hour working day. On average what noise level is this worker exposed to? (round to the nearest whole number)

Answer 1

first exposure = 98(5) dBhours
2nd exposure = 82(3) dBhours

average exposure = (490+246)dBhours/8 hours
= 92 dB

this would make "mathematical" sense, I don't know if it works that way in reality