An artillery shell is launched on a flat, horizontal field at an angle of α = 36.2° with respect to the horizontal and with an initial speed of v0 = 318 m/s. What is the horizontal distance covered by the shell after 7.68 s of flight?

Question

I'm confused on how to even begin this problem.

Answer 1

horizontal speed is

318 cos 36.2° = 256.613 m/s

So, how far does it travel in 7.68s?

Remember that the horizontal speed does not change after takeoff. The only force acting is the vertical pull of gravity.