k = 0.693/t1/2
ln(No/N) = kt
No = 100 (but you can start with any number you wish but with any other starting value you must calculate percentage differently.
N = ?
k from above
time = from the problem
Solve for N and since you started with 100 that is the percent remaining undecayed.
Technetium-99m, an important radionuclide in medicine, has a half-life of 6.0 hours. What percentage of a sample of technetium-99m will remain undecayed after the following times?
18.0 hours
1 day
5 half- lives
1 answer
1 answer