Asked by Cort
An artist makes a profit of (500p - p^2) dollars from selling p paintings. What is the fewest number of paintings the artist can sell to make a profit of at least $60,000?
Don't know how to even set it up
Don't know how to even set it up
Answers
Answered by
Steve
just use what you are given:
500p - p^2 >= 60000
Now, just from what you know about parabolas, you know that the parabola opens downward. So, the portion of the curve above a horizontal line (here, y=60000) will lie between the roots of
500p - p^2 - 60000 = 0
The roots are 200, 300.
So, selling anywhere between 200 and 300 paintings will result in a profit of at least 60,000.
See
http://www.wolframalpha.com/input/?i=500p+-+p^2+%3E%3D+60000
500p - p^2 >= 60000
Now, just from what you know about parabolas, you know that the parabola opens downward. So, the portion of the curve above a horizontal line (here, y=60000) will lie between the roots of
500p - p^2 - 60000 = 0
The roots are 200, 300.
So, selling anywhere between 200 and 300 paintings will result in a profit of at least 60,000.
See
http://www.wolframalpha.com/input/?i=500p+-+p^2+%3E%3D+60000
Answered by
Anonymous
150
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