Asked by hiedi

Combustion analysis of 1.0g of a compound containing carbon , hydrogen and oxygen gives 2.3 g of carbon dioxide and 0.93g of water . If The relative molecular mass is 58. Calculate The empirical and molecular formula
Answered by DrBob222
Where are you with this one?
Convert mass CO2 to mass C.
Convert mass H2O to mass H(atoms).
1.0g - mass C - mass H = mass O

Convert g C to mols.
Convert g H to mols
Convert g O to mols.

Find the ratio for the empirical formula.
Then (emprical formula) x number = molar mass. Solve for number (rounded to whole number).
Then (empirical formula)<sub>n</sub> = molecular formula.
Answered by MALLIKARJUN N
Good
Answered by Kaela
1.23
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