Asked by hiedi
                Combustion analysis of 1.0g of a compound containing carbon , hydrogen and oxygen gives 2.3 g of carbon dioxide and 0.93g of water . If The relative molecular mass is 58.  Calculate The empirical and molecular formula 
            
            
        Answers
                    Answered by
            DrBob222
            
    Where are you with this one?
Convert mass CO2 to mass C.
Convert mass H2O to mass H(atoms).
1.0g - mass C - mass H = mass O
Convert g C to mols.
Convert g H to mols
Convert g O to mols.
Find the ratio for the empirical formula.
Then (emprical formula) x number = molar mass. Solve for number (rounded to whole number).
Then (empirical formula)<sub>n</sub> = molecular formula.
    
Convert mass CO2 to mass C.
Convert mass H2O to mass H(atoms).
1.0g - mass C - mass H = mass O
Convert g C to mols.
Convert g H to mols
Convert g O to mols.
Find the ratio for the empirical formula.
Then (emprical formula) x number = molar mass. Solve for number (rounded to whole number).
Then (empirical formula)<sub>n</sub> = molecular formula.
                    Answered by
            MALLIKARJUN N
            
    Good 
    
                    Answered by
            Kaela
            
    1.23
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.