Asked by Joe
Express y as a function of x. What is the domain? Explain your answer.
log4y = x + log4
Solving exponential equations with logarithms
Solve to the nearest thousandth.
5^1+x = 2^1-x
log4y = x + log4
Solving exponential equations with logarithms
Solve to the nearest thousandth.
5^1+x = 2^1-x
Answers
Answered by
Steve
If you mean
log(4y) = x + log(4)
Then you have
log(4y/4) = x
log(y) = x
x = 10^y
Assuming the usual lack of care with parentheses, I'll guess you mean
5^(1+x) = 2^(1-x)
5*5^x = 2 * 1/2^x
(5/2) = 1/(10^x)
10^x = 2/5
x = log(2/5)
log(4y) = x + log(4)
Then you have
log(4y/4) = x
log(y) = x
x = 10^y
Assuming the usual lack of care with parentheses, I'll guess you mean
5^(1+x) = 2^(1-x)
5*5^x = 2 * 1/2^x
(5/2) = 1/(10^x)
10^x = 2/5
x = log(2/5)