This is a limiting reagent (LR) problem.
mols Mg = 10.2/24.3 = about 0.42 but you need a more accurate answer.
mols O2 = 11.8/32 = about 0.37 and
2 mols MgO/1 mol O2 = about 0.42/2 = about 0.21 and you have that much O2. Therefore, Mg must the LR.
mols Mg = 0.42
mols MgO produced = 0.42
g MgO = mols MgO x molar mass MgO = ?
Magnesium oxide can be made by heating magnesium metal in the presence of the oxygen. The balanced equation for the reaction is
2Mg(s)+O2(g)�¨2MgO(s)
When 10.2 g Mg is allowed to react with 10.6 g O2, 11.8 g MgO is collected.
Determine the theoretical yield for the reaction.
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