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Asked by anon

sin θ=2/3 and θ correspond to a point in quadrant 2. cos θ=
10 years ago

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Answered by Steve
sinθ = y/r
So, in QII,
y = 2
r = 3
x = -√5

Now, cosθ = x/r = ?
10 years ago
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sin θ=2/3 and θ correspond to a point in quadrant 2. cos θ=

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