Asked by anon
sin θ=2/3 and θ correspond to a point in quadrant 2. cos θ=
Answers
Answered by
Steve
sinθ = y/r
So, in QII,
y = 2
r = 3
x = -√5
Now, cosθ = x/r = ?
So, in QII,
y = 2
r = 3
x = -√5
Now, cosθ = x/r = ?
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