Asked by Daisy

I = Alog10(t) + B

I equals 8 when t is 3
I equals 50 when t is 8
t can't go past 200

A and B are constants

Find A and B when I reaches 100
Answered by bobpursley
8=Alog3+B
50=Alog8+B
subtract the first from the second
42=a(log8-log3)
42=a(log(8.3))
solve for A

then
hmmm. wondering if ou meant when t=100...
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