Asked by Rach
I keep getting the wrong answer?
I know there is one similar to this on here but I keep getting the wrong answer.
The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6×10^−3mm. If a single gold atom has a diameter of 2.9×10^−8 cm, how many atoms thick was Rutherford's foil?
I convert 6×10^−3mm to cm and got 6x10^-4cm
6x10^-4cm/2.9x10^-8cm= 2.0689655e-12?
is that right or did I do something wrong?
I know there is one similar to this on here but I keep getting the wrong answer.
The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6×10^−3mm. If a single gold atom has a diameter of 2.9×10^−8 cm, how many atoms thick was Rutherford's foil?
I convert 6×10^−3mm to cm and got 6x10^-4cm
6x10^-4cm/2.9x10^-8cm= 2.0689655e-12?
is that right or did I do something wrong?
Answers
Answered by
bobpursley
Nuts to your math.
numberatomsthick=thickness/thickone
=6E-3mm/2.9E-7mm= 6/2.9 E5 atoms.
numberatomsthick=thickness/thickone
=6E-3mm/2.9E-7mm= 6/2.9 E5 atoms.
Answered by
DrBob222
I get 6E-3/2.9E-7 = 2E4
Answered by
bobpursley
drBob is right, goodness, 7-3 is E4
Answered by
Rach
Thank you for the help everyone!
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