Question

I keep getting the wrong answer?
I know there is one similar to this on here but I keep getting the wrong answer.
The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6×10^−3mm. If a single gold atom has a diameter of 2.9×10^−8 cm, how many atoms thick was Rutherford's foil?

I convert 6×10^−3mm to cm and got 6x10^-4cm

6x10^-4cm/2.9x10^-8cm= 2.0689655e-12?
is that right or did I do something wrong?

Answer 1

Nuts to your math.

numberatomsthick=thickness/thickone
=6E-3mm/2.9E-7mm= 6/2.9 E5 atoms.

Answer 2

I get 6E-3/2.9E-7 = 2E4

Answer 3

drBob is right, goodness, 7-3 is E4

Answer 4

Thank you for the help everyone!