Asked by Chloe

A cash drawer has $267.00 total. There are no bills larger than a 10. There are 11 tens and 7 more 1s than 5s. How many of each bill is there?
Answered by Steve
To find the number of $5 bills, add up the value of all the bills and solve for f:

10*11 + 5*f + 1*(f+7) = 267
Answered by Chloe
110.00 + 125.00 + 32.00 =267.00
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