it takes 1.107 s to fall 6m.
So, the horizontal velocity must be at least 10m/1.107s = 9.037 m/s
I think you can now do the rest. Figure how long it takes to fall the remaining 4 meters to the bottom of the canyon. Then use that to find the horizontal distance moved.
You are standing at the top of a cliff that has a stairstep configuration. There is a vertical drop of 6 m at your feet, then a horizontal shelf of 10 m, then another drop of 4 m to the bottom of the canyon, which has a horizontal floor. You kick a 0.76 kg rock, giving it an initial horizontal velocity that barely clears the shelf below.
1.) What initial horizontal velocity v will be required to barely clear the edge of the shelf below you? The acceleration of gravity is 9.8 m/s2 . Consider air friction to be negligible.
2.)How far from the bottom of the second cliff will the projectile land?
3 answers
@Steve, thank you so much!
just crank 90's in fornite you will figure it out