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A 56.59 g sample of a substance is initially at 20.5 °C. After absorbing 1267 J of heat, the temperature of the substance is 11...Asked by Angel
A 43.70 g sample of a substance is initially at 24.7 °C. After absorbing 1757 J of heat, the temperature of the substance is 120.5 °C. What is the specific heat (c) of the substance?
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Answered by
DonHo
q=m*c*deltaT
q=heat energy
m=mass
c=specific heat
deltaT= T_final - T_initial
q=heat energy
m=mass
c=specific heat
deltaT= T_final - T_initial
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