Asked by katy
A circle has a center at (8,2). The point is (3,7) is on the circle. What is the area of the circle to the nearest tenth of a square unit?
A. 22.2
B. 44.4
C. 157.1
D. 314.2
(I've been stuck on this question for a while) thanks!!
A. 22.2
B. 44.4
C. 157.1
D. 314.2
(I've been stuck on this question for a while) thanks!!
Answers
Answered by
Steve
The circle is
(x-8)^2 + (y-2)^2 = r^2
Plug in your point (3,7) and you have
(3-8)^2 + (7-2)^2 = r^2
Now that you have r^2, you know the area is just pi r^2
(x-8)^2 + (y-2)^2 = r^2
Plug in your point (3,7) and you have
(3-8)^2 + (7-2)^2 = r^2
Now that you have r^2, you know the area is just pi r^2
Answered by
katy
I still don't get the answer steve? I calculated, but nothing close.
Answered by
Steve
Hmmm. Let's see.
r^2 = 5^2+5^2 = 50
The area is πr^2, or 50*3.14159 = 157.09
Looks like C to me.
If you try stuff and it seems wrong, you really should post your work, so we can help fix it.
r^2 = 5^2+5^2 = 50
The area is πr^2, or 50*3.14159 = 157.09
Looks like C to me.
If you try stuff and it seems wrong, you really should post your work, so we can help fix it.
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