Question

A 10.0 kg object is resting on a horizontal surface with a coefficient of friction of 0.7. Determine the minimum force that can move the object.At what inclination should force be applied?
M*g = 10 * 9.8 = 98 N. = Wt. of object = Normal(Fn).

Fs = u*Fn = 0.7 * 98 = 6.86 N. = Force of static friction.

F-Fs = M*a.
F-6.86 = 10*0 = 0.
F = 6.86 N.

Angle = 0o(parallel to the surface).

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