Asked by Jay
You are standing on a 50m cliff and throw a ball upwards at 8.2m/s
- calculate the maximum height the ball will reach
- calculate the time it will take the ball to return where it started
- calculate the speed of the ball when it hits the ground.
Please help
- calculate the maximum height the ball will reach
- calculate the time it will take the ball to return where it started
- calculate the speed of the ball when it hits the ground.
Please help
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h.
V = 0.
Vo = 8.2 m/s.
g = -9.8 m/s^2.
h = ?
V = Vo + g*Tr.
V = 8.2 m/s.
Vo = 0.
g = -9.8 m/s^2.
Tr = ? = Rise time.
Tf = Tr = Fall time.
Tr+Tf = Time to return to starting point.
V^2 = Vo^2 + 2g*h.
Vo = 8.2 m/s.
g = +9.8 m/s^2.
h = 50 m.
V = ?.
V = 0.
Vo = 8.2 m/s.
g = -9.8 m/s^2.
h = ?
V = Vo + g*Tr.
V = 8.2 m/s.
Vo = 0.
g = -9.8 m/s^2.
Tr = ? = Rise time.
Tf = Tr = Fall time.
Tr+Tf = Time to return to starting point.
V^2 = Vo^2 + 2g*h.
Vo = 8.2 m/s.
g = +9.8 m/s^2.
h = 50 m.
V = ?.
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