Asked by sabrina

For the decomposition of gaseous dinitrogen pentoxide (shownbelow),
2 N2O5(g).....> 4NO2(g) + O2(g)
the rate constant is k = 2.8 10-3 s-1 at 60°C. The initial concentration of N2O5 is 1.52 mol/L.


(a) What is [N2O5] after 5.00 min?
_____mol/L
(b) What fraction of the N2O5 has decomposed after 5.00 min?
_____

Answers

Answered by DrBob222
The unit in the problem for k is sec-1 which means this is a first order reaction.
ln(No/N) = kt
No = 1.52 M
N = ?
k = given
t = 5 min
Solve for N.


For part b, You know No and N, fraction remaining is N/No. Subtract from 1.0 to find fraction decomposed.

Post your work if you get stuck.
Answered by Anonymous
1.01
0.57
Answered by Anonymous
The rate constant for the first order decomposition at 45 o
C of dinitrogen pentaoxide, N2O5, dissolved in
chloroform, CHCl3, is 6.2 x 10-4 min-1
2N2O5 → 4NO2 + O2
What is the rate of decomposition of N2O5 and rates of formation of NO2 and O2 when the concentration of N2O5 is
0.4 mol.dm-3
.
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