It's neither of your proposals.
It's mols ethanol = 2.2/46.08 = ?
Then mols C = 2*mols ethanol.
Calculate the number of moles of carbon
atoms present in 2.2 g of ethanol (C2H6O).
For this question, I would just need to find the molar mass of carbon, right? Not the molar mass of all of ethanol? So it would just be 2.2 g/ 24.02 g/mol which would equal .092. It wouldn't be 2.2 g/ 46.08 g/mol because it's only asking for carbon, right? I just want to make sure I am doing this problem correctly.
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