Asked by SARA
                20.) How do I find the zeros of the function algebraically? 
ex1) f(x)= x^3 -4x^2 -9x +36
ex3) f(x)= 3 +(5/x)
ex7) f(x) = (2x^2-9)/ (3-x)
            
            
        ex1) f(x)= x^3 -4x^2 -9x +36
ex3) f(x)= 3 +(5/x)
ex7) f(x) = (2x^2-9)/ (3-x)
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