Asked by TayB
Find the instantaneous velocity, using limits, for the given value of t of an object moving according the given equation.
a. s(t)=t^2–8t+18 ; t=3
b. 𝑠(𝑡)=1/t^2 ; t=1
a. s(t)=t^2–8t+18 ; t=3
b. 𝑠(𝑡)=1/t^2 ; t=1
Answers
Answered by
Steve
v(t) = ds/dt, so
(a) v(t) = 2t-8
(b) v(t) = -2/t^3
Just plug in your numbers.
(a) v(t) = 2t-8
(b) v(t) = -2/t^3
Just plug in your numbers.
Answered by
TayB
steve i got that for a but we werent allowed to use derivative rules to get the answer because we havent learned those yet. and from getting 2t-8 would i just plug in 3 for t because if so i got -2
Answered by
Steve
yes.
I forgot that it said "using limits". Sorry. It's just back to basics.
I forgot that it said "using limits". Sorry. It's just back to basics.
Answered by
TayB
Thanks for your help Steve. I appreciate it. and yes it is back to basic tedious work where as doing it using derivatation is a lot less steps
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