HUH ?
set to 0
15 - 3 x = 0
3 x = 15
x = 5
12 - x^2 = 5*0 = 0
x^2 = 12
x = +/- sqrt 12 = +/- 2 sqrt 3
How do you find all real values of x such that f(x)=0?
Example 1: f(x)=15-3x
Example 2: f(x)= (12-x^2)/5
Example 3: f(X)= x^3 -x
2 answers
x^3 - x = 0
x (x^2-1) = 0
x (x-1)(x+1) = 0
x = 0
x = 1
x = -1
x (x^2-1) = 0
x (x-1)(x+1) = 0
x = 0
x = 1
x = -1