Find the slope of the tangent line at x=3

F(x)=-2x+1

[-2(3+h)+1] - [-2(3)+1]
÷
h

2 answers

but it is a straight line of form
y = m x + b
where m is the slope = 2
but oh well, we can take the derivative

{[+2(3+h)+1] - [+2(3)+1] }/h
note + 2 not -

[6 + 2 h +1 - 6 -1 ] / h

2 h/h

2
Good work, Damon, but the slope was in fact -2.