Asked by deee
domain of 16x^2+8x-1?
Answers
Answered by
Reiny
if you meant
y = 16x^2 + 8x - 1
x of the vertex is -8/32 = -1/4
y = 16(1/16) + 8(-1/4) - 1
= -2
vertex is (-1/4), -2) and the parabola opens up
the domain of any "vertical" parabola is
x is any real number
confirmation:
http://www.wolframalpha.com/input/?i=y+%3D+16x%5E2+%2B+8x+-+1
y = 16x^2 + 8x - 1
x of the vertex is -8/32 = -1/4
y = 16(1/16) + 8(-1/4) - 1
= -2
vertex is (-1/4), -2) and the parabola opens up
the domain of any "vertical" parabola is
x is any real number
confirmation:
http://www.wolframalpha.com/input/?i=y+%3D+16x%5E2+%2B+8x+-+1
Answered by
deee
domain of 16x+5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.