pH = pK2 + log(base)/(acid)
7.4 = pK2 + log (base)/(acid)
Solve for (base)/(acid) = ?. That is equation 1.
Then
base + acid = 500 x 0.3 is equation 2.
Solve those two equations simultaneously for base and acid (in millimoles since 500 x 0.3 gives millimols).
That gives you millimols base and millimols acid. I would convert to mols, then grams = mols x molar mass.
To prepare 500.00 mL of 0.300 M buffer with a pH of 7.4. NaH2PO4/Na2HPO4 How many grams of each should be added to the 500.00mL flask to create this buffer?
1 answer
1 answer