Asked by Rose

Given y=2x^2-10x. Find all real values of x for which y=-3

10 years ago

Answered by Reiny

solve 2x^2 - 10x = 3

2x^2 - 10x - 3 = 0

which methods have you learned to solve a quadratic?

10 years ago

Answered by Reiny

I have a copy error, should have been

solve 2x^2 - 10x = -3

2x^2 - 10x + 3 = 0

10 years ago

There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer

We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.