Given y=2x^2-10x. Find all real values of x for which y=-3

Answer 1

solve 2x^2 - 10x = 3

2x^2 - 10x - 3 = 0

which methods have you learned to solve a quadratic?

Answer 2

I have a copy error, should have been

solve 2x^2 - 10x = -3

2x^2 - 10x + 3 = 0