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Rose
Given y=2x^2-10x. Find all real values of x for which y=-3
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Answered by
Reiny
solve 2x^2 - 10x = 3
2x^2 - 10x - 3 = 0
which methods have you learned to solve a quadratic?
Answered by
Reiny
I have a copy error, should have been
solve 2x^2 - 10x = -3
2x^2 - 10x + 3 = 0
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