Asked by Marie
Suppose an object is dropped from a height h0 above the ground. Then its height after t seconds is given by h=−16t^2+h0, where h is measured in feet. If a ball is dropped from 48 feet above the ground, how long does it take to reach ground level?
Answers
Answered by
Steve
just plug in 48 for h0, and solve for t when h(t) = 0. Just the usual quadratic stuff.
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