t = d/4.09
and
t = (20.9 + d)/6.04
so
d/4.09 = (20.9 + d)/6.04
d + 20.9 = 1.48 d
.48 d = 20.9
d = 20.9/.48 meters
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.09 m/s. The car is a distance d away. The bear is 20.9 m behind the tourist and running at 6.04 m/s. The tourist reaches the car safely. What is the maximum possible value for d?
I don't know where to start or what to do
1 answer