Asked by bob
Can you simplify
(2x^-4 y^-1 times 2y^4 z^-1)^-2/ 2yx^3 z^0
I got the numerator to be
16x^16 y^17 z
and then divided by the denominator to get
8x^13y^16z
(2x^-4 y^-1 times 2y^4 z^-1)^-2/ 2yx^3 z^0
I got the numerator to be
16x^16 y^17 z
and then divided by the denominator to get
8x^13y^16z
Answers
Answered by
Reiny
Have to make an assumption like I had to yesterday:
(2 x^-4 y^-1)(2 y^4 z^-1)^-2/ (2yx^3 z^0)
= 4x^0 y^-1 z^-1/(2yx^3) , since z^0=1
= 4(1/y)(1/z)(1/(2yx^3)
= <b>4/(x^3 y^2 z)</b>
or
= 4 x^-3 y^-2 z^-1
(2 x^-4 y^-1)(2 y^4 z^-1)^-2/ (2yx^3 z^0)
= 4x^0 y^-1 z^-1/(2yx^3) , since z^0=1
= 4(1/y)(1/z)(1/(2yx^3)
= <b>4/(x^3 y^2 z)</b>
or
= 4 x^-3 y^-2 z^-1
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