Asked by Collins
(1):Y=|n(3x^2+2)
(2):y=e^(x^3+x)
(2):y=e^(x^3+x)
Answers
Answered by
Reiny
y = ln(3x^2 + 2)
dy/dx = 6x/(3x^2 + 2)
y = e^(x^3 + x)
dy/dx = (3x^2 + 1) e^(x^3 + x)
dy/dx = 6x/(3x^2 + 2)
y = e^(x^3 + x)
dy/dx = (3x^2 + 1) e^(x^3 + x)
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