what is the range for the function j(x)=5+sqrt of 2-x

Answer 1

I assume you mean

j(x) = 5 + √(2-x)

remember we cannot take the √ of a negative, so
2-x ≥ 0
-x ≥ -2
x ≤ 2 for the domain

the minimum value of j(x) is 5
so range: y ≥ 5