Asked by anon
what is the range for the function j(x)=5+sqrt of 2-x
Answers
Answered by
Reiny
I assume you mean
j(x) = 5 + √(2-x)
remember we cannot take the √ of a negative, so
2-x ≥ 0
-x ≥ -2
x ≤ 2 for the domain
the minimum value of j(x) is 5
so range: y ≥ 5
j(x) = 5 + √(2-x)
remember we cannot take the √ of a negative, so
2-x ≥ 0
-x ≥ -2
x ≤ 2 for the domain
the minimum value of j(x) is 5
so range: y ≥ 5
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