Question
there are 40 bikes inspected. If 15 need new tires and 26 need gear repairs.
-what is the greatest number of bikes that could have needed both repairs?
-The least number that could have needed both?
-Greatest number that could have needed neither repair?
-what is the greatest number of bikes that could have needed both repairs?
-The least number that could have needed both?
-Greatest number that could have needed neither repair?
Answers
PsyDAG
No more than 15 will need both repairs.
Since 15 + 26 = 41, at least one will need both.
40 - 26 = 14 could need neither.
Since 15 + 26 = 41, at least one will need both.
40 - 26 = 14 could need neither.