Asked by Ken
Hydrogen sulfide burns in oxygen to form sulfur dioxide and water. If sulfur dioxide is being formed at a rate of 0.19 mol L-1 s-1, what are the rates of disappearance of hydrogen sulfide and oxygen?
rate of disappearance of O2?
rate of disappearance of H2S?
I got :
rate of disappearance of H2S = 0.19 mol L-1 S-1
rate of disappearance of O2 = 0.29 mol L-1 S-1
but when I checked the answer, it turned out wrong answer.
Am I doing something wrong?
rate of disappearance of O2?
rate of disappearance of H2S?
I got :
rate of disappearance of H2S = 0.19 mol L-1 S-1
rate of disappearance of O2 = 0.29 mol L-1 S-1
but when I checked the answer, it turned out wrong answer.
Am I doing something wrong?
Answers
Answered by
DrBob222
For O2 I would have rounded 0.285 to 0.28 and I think both should have a - sign. Personally, I think the words "rate of disappearance" should take care of the negative sign but sometimes that isn't so.
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