Asked by Ken
The radioactive isotope, phosphorus-32, has a half-life of 14.26 days. How much phosphorus-32 will remain after 60 days?
Please help.
Please help.
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
Substitute k into the below equation.
ln(No/N) = kt
No = The problem doesn't say how much to start with so start with 100 grams.
N = what you end up with after 60 days.
k from above.
t = 60 days
Starting with 100 g will give you a fraction and that x 100 will give you a percentage of the amount you start with that will remain after 60 days.
Substitute k into the below equation.
ln(No/N) = kt
No = The problem doesn't say how much to start with so start with 100 grams.
N = what you end up with after 60 days.
k from above.
t = 60 days
Starting with 100 g will give you a fraction and that x 100 will give you a percentage of the amount you start with that will remain after 60 days.
Answered by
ajayi
3.743
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