I find the explanation of the problem quite unclear. Here is one guess:
If you mean the volume of the material used, then if the outside radius is R, and the inside radius is r, the volume of material is
2π/3 (R^3-r^3)
Assuming the outside radius is 40ft and the thickness is 6cm, we have (since 1 ft = 30.48 cm),
2π/3 [(40*30.48)^3 - (40*30.48-6)^3] cm^3
Evaluate that. I also suspect a units typo. But you can fix that, right?
a hemisphere dome on top of a silo has a diameter of 40 feet, find the volume of the dome r=6cm
v=4/3 times 3.14 times radius6cubed
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