Asked by Janet
a hemisphere dome on top of a silo has a diameter of 40 feet, find the volume of the dome r=6cm
v=4/3 times 3.14 times radius6cubed
v=4/3 times 3.14 times radius6cubed
Answers
Answered by
Steve
I find the explanation of the problem quite unclear. Here is one guess:
If you mean the volume of the material used, then if the outside radius is R, and the inside radius is r, the volume of material is
2π/3 (R^3-r^3)
Assuming the outside radius is 40ft and the thickness is 6cm, we have (since 1 ft = 30.48 cm),
2π/3 [(40*30.48)^3 - (40*30.48-6)^3] cm^3
Evaluate that. I also suspect a units typo. But you can fix that, right?
If you mean the volume of the material used, then if the outside radius is R, and the inside radius is r, the volume of material is
2π/3 (R^3-r^3)
Assuming the outside radius is 40ft and the thickness is 6cm, we have (since 1 ft = 30.48 cm),
2π/3 [(40*30.48)^3 - (40*30.48-6)^3] cm^3
Evaluate that. I also suspect a units typo. But you can fix that, right?
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