If N = a-b^a-b, what is the value of N when a=2 and b=2 ?

Question

THANK YOU :)

Answer 1

taking your typing at face-value, since you have no brackets

N = a-b^a - b, for the given values
= 2 - 2^2 - 2
= 2 - 4 - 2
= -4