Asked by Camz
If N = a-b^a-b, what is the value of N when a=2 and b=2 ?
THANK YOU :)
THANK YOU :)
Answers
Answered by
Reiny
taking your typing at face-value, since you have no brackets
N = a-b^a - b, for the given values
= 2 - 2^2 - 2
= 2 - 4 - 2
= -4
N = a-b^a - b, for the given values
= 2 - 2^2 - 2
= 2 - 4 - 2
= -4
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