Asked by Michael
On Line ABCDE
If BD exceeds CD by 10 and
If BD=x^2 and CD = x + 4, compute x.
I tried:
BD = CD + 10
X^2 = (x+4)+10
x^2 = x+14
That's where I get stuck.
Do I convert to:
x^2 - x -14 = 0 ?
If so, how do I solve for x?
Thank you in advance for any assistance!
Answers
Answered by
Steve
Assuming your math is ok as far as it went, have you not learned the quadratic formula? Use it, or solve by completing the square:
x^2-x-14 = 0
x^2-x = 14
x^2 - x + 1/4 = 14 + 1/4
(x - 1/2)^2 = 57/4
x = 1/2 ±√(57/4)
x = (1±√57)/2
x^2-x-14 = 0
x^2-x = 14
x^2 - x + 1/4 = 14 + 1/4
(x - 1/2)^2 = 57/4
x = 1/2 ±√(57/4)
x = (1±√57)/2
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