Question
A 6 feet tall man walks away from a streetlight that is 15 feet high at a rate of 5 ft/s. Express the length 's' of his shadow as a function of time.
What I have so far:
I set up a triangle and used similar triangles to create a ratio
(6/s) = (s/d+s)
s = (6d + 30/15s)
And I'm stuck...
Please help!
What I have so far:
I set up a triangle and used similar triangles to create a ratio
(6/s) = (s/d+s)
s = (6d + 30/15s)
And I'm stuck...
Please help!
Answers
Steve
d = 5t, so
6/s = 15/(5t+s)
6(5t+s) = 15s
30t = 9s
s = 30/9 t
6/s = 15/(5t+s)
6(5t+s) = 15s
30t = 9s
s = 30/9 t