since 1L = 1000 cm^3, if the height ish, then we know that
(20)(15)(h) = 4800
h = 16
So, the wet surface area is
bottom + 2 long sides + 2 short sides
= 20*15 + 2*16(20+15)
= 1420 cm^2
(20)(15)(h) = 4800
h = 16
So, the wet surface area is
bottom + 2 long sides + 2 short sides
= 20*15 + 2*16(20+15)
= 1420 cm^2
Volume = length × width × height
Given that the volume is 4.8 liters and the length and width of the tank are 20 cm and 15 cm respectively, we can rearrange the formula to calculate the height:
4.8 liters = 20 cm × 15 cm × height
First, let's convert 4.8 liters to cubic centimeters (since the other measurements are in centimeters). Since 1 liter is equal to 1000 cubic centimeters:
4.8 liters = 4.8 × 1000 = 4800 cubic centimeters
Now we can substitute this value into the equation and solve for the height:
4800 cm³ = 20 cm × 15 cm × height
Divide both sides of the equation by (20 cm × 15 cm):
height = 4800 cm³ / (20 cm × 15 cm)
height = 4800 cm³ / 300 cm²
height = 16 cm
So, the height of the water level in the tank is 16 cm.
To calculate the total surface area of the cuboid in contact with the water, we need to find the areas of the four sides and the top (assuming there is no bottom).
The surface area of a rectangular side is given by the formula:
Area = length × height
Since we know the length of 20 cm and the height of 16 cm, we can calculate the area for each of the four sides:
Area of the two shorter sides = 20 cm × 16 cm = 320 cm² each
Area of the two longer sides = 15 cm × 16 cm = 240 cm² each
The surface area of the top is given by the formula:
Area = length × width
Substituting the measurements, we get:
Area of the top = 20 cm × 15 cm = 300 cm²
To find the total surface area, we add up the areas of all the sides:
Total surface area = 2 × (Area of the two shorter sides) + 2 × (Area of the two longer sides) + Area of the top
Total surface area = 2 × 320 cm² + 2 × 240 cm² + 300 cm²
Total surface area = 640 cm² + 480 cm² + 300 cm²
Total surface area = 1420 cm²
Therefore, the total surface area of the cuboid in contact with the water is 1420 cm².