Asked by Alyssa
A Bugatti Veyron 16.4 can accelerate from 0 to 60 mi/h in 2.4 s. The Saleen S7 Twin Turbo goes "from 0 to 60" in 2.8 s. Determine the distance that the Bugatti Veyron would travel in the time it takes to reach 75 km/h, the speed limit on many Canadian roads. Compare your answer to the distance that the Saleen S7 Twin Turbo would travel while accelerating to the same final speed.
Answers
Answered by
Damon
Bug dv/dt = ab = 60 mi/h/2.4s = 25 mi/(s h)
= 40.2 km /(3600 s^2)
Sal dv/dt = as = 60/2.8 = 21.4 mi/(s h)
=34.4 km/3600s^2
v = 75 km/h = 75 km/3600s
then v = a t or t = v/a
Bug:
t = 75 km/3600 s / 40.2 km/3600s^2
= 1.87 seconds
d = (1/2) a t^2 =
OR
use half max (average) speed
Vaverage = 75/(2*3600 )km/s
d = 1.87 * 75/(2*3600) = .0195 km
= 19.5 meters
do the same for the other car
= 40.2 km /(3600 s^2)
Sal dv/dt = as = 60/2.8 = 21.4 mi/(s h)
=34.4 km/3600s^2
v = 75 km/h = 75 km/3600s
then v = a t or t = v/a
Bug:
t = 75 km/3600 s / 40.2 km/3600s^2
= 1.87 seconds
d = (1/2) a t^2 =
OR
use half max (average) speed
Vaverage = 75/(2*3600 )km/s
d = 1.87 * 75/(2*3600) = .0195 km
= 19.5 meters
do the same for the other car
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